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∫_0^a f(x)dx = ∫_0^a f(a−x)dx
∫_0^a f(x)dx = ∫_0^a f(a−x)dx (∫_0^a f(x)dx = ∫_0^a f(a−x)dx)
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∫_0^a f(x)dx = ∫_0^a f(a−x)dx
When to use this
Special case of King on [0,a].